Q. I have a geometry question that Im completely lost on! Its about inscribed angles but more specifically, its a quadrilateral in a circle. Its asking me to find the measure of angle B. Arc AB equals 92 and Arc BC equals 80. Help?
A. arc BC = 360-(92+80) = 188
so since an inscribed angle equals
half of its intercepted arc
then angle B=94
so since an inscribed angle equals
half of its intercepted arc
then angle B=94
How to solve for inscribed angles?
Q. Angle C is an inscribed angle of circle P. Angle C measures (16x â 1)° and arc AB measures (20x + 10)°. Find x.
A. (20x + 10)/2 = 16x - 1
10x + 5 = 16x - 1
6x = 6
x = 1
I hope this helps!
10x + 5 = 16x - 1
6x = 6
x = 1
I hope this helps!
angle difference when seen in a circle and on a straight plane?
Q. An inscribed angle in a circle when measured with specific equipment turns out to be 100 degrees. That same angle when measured on a straight plane with specific equipment turns out to be 95 degrees. Why is there this difference?
Thanks beforehand
Thanks beforehand
A. the circle lies on a different plane.
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